- Izak609
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- Exalted Legendary Member
Exalted Unexplainable Member
I'm pointing out that the correct way to find the correct average in this situation is to take the ratio out of the equation then slap it back in. Fifteen to three right? 15 + 3 = 18 and 3 + 15 = 18 and 18 / 18 = 1 and one just so happens to that number I've been talking about. Yes, this isn't an average of ratios, because the average of ratios is a rather meaningless statistic, because of the properties of ratios.
Take the death to kill ratio from your example. One player had a death to kill ratio of 5 and the other of .2, the average of this is 2.6. Turn the death to kill ratio of 2.6 into the kill to death ratio of .385... . So, does the kill to death ratio of .385... have any relevancy in this discussion?
Posted by: chrishans
No. An average of averages (i.e. K/D ratios) doesn't necessarily equal 1.
Then your mathematics are irrelevant to this discussion, I presumed otherwise. Either way, I'm done talking, if this post doesn't change your take on it, it isn't worth the effort to further argue and I can't change your opinion.
Posted by: Sentox6
Posted by: Izak609
Your mathematics are inferring that there where more kills then deaths...My mathematics are not implying any such thing. You are inferring incorrectly from my mathematics, which is something else entirely.