- Backfjre
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- Honorable Member
Posted by: Backfjre
Okay random input, if the PoA was near the equator and launching in the same direction as the rotation of Reach, that would make it significantly easier to lift off.
Earth rotates at 1000mph ish (simple number for the sake of the argument)
To break the atmosphere (the measurement I don't recall exactly) going against the Earth's rotation would both have to be enough to break atmosphere AND overcome this 1000 mph spin, while going with the rotation would make it 1000mph easier to escape atmosphere.
So depending on the direction of launch, the math could imply that the Pillar of Autumn was traveling as much as thousands of miles per hour faster.
So... just throwing it out there.
Okay super edit, did some research on Reach to get a more solid argument.
Reach has a 27 hour day, and a diameter of 9490 miles. Which puts the circumference of Reach at ~29,834 miles.
So ~29,834/27 = ~1,104
Reach rotates at the equator at ~1,104 miles per hour.
So should The Pillar of Autumn be launching in the direction of Reach's rotation (from West to East, which it is) and is relatively close to the equator (which several cutscenes suggest)then The Pillar of Autumn would need ~1,104 mph less thrust to help it escape atmosphere.