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Subject: Mail Sack!
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Steepness angle = sin^-1 (1-(a/2(pi)))

I'll admit I did some reading to try to find that, and it sounds/looks like it works.

  • 07.13.2012 1:41 PM PDT

"The Moving Finger writes; and, having writ,
Moves on: nor all thy Piety nor Wit,
Shall lure it back to cancel half a Line,
Nor all thy Tears wash out a Word of it."
-Omar Khayyám-


Posted by: RocketMoose
Posted by: Hylebos
Posted by: MozzarellaMonky
h is the height
Ahh, but what is the height in terms of a and r is the question?

:)


Imaginary bonus points for the answer to this one! :)
(I'm guessing Hylebos already solved it - if so, give others a shot at imaginary glory)


42

  • 07.13.2012 1:43 PM PDT
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Posted by: DeeJ
Posted by: xNiGhThAwKx19
Answer in degrees to the riddle:

[quote]arccos(1-a/360)


Winner.

Send me a message. Name, Address, Size.


Wow, campers win. Dangit! I don't like extremely time sensitive ones.

Edit: Oh, and 77th!

[Edited on 07.13.2012 1:43 PM PDT]

  • 07.13.2012 1:43 PM PDT

sqrt{(r^2)*a/pi[1+a/(4*pi)]}

Imaginary point pls

  • 07.13.2012 1:44 PM PDT

In a time long past, the armies of the dark came again to the lands of men. Their leaders became known as the fallen lords, and their terrible sorcery was without equal in the west.
In 30 years they reduced the civilized nations into carrion and ash. Until the free city of Madrigal alone defined them. An army gathered there, and a desperate battle was joined against the fallen
Heros were born in the fire and bloodshed of the wars which followed and their names and deeds will never be forgotten


Posted by: ZosoAchilles
sqrt{(r^2)*a/pi[1+a/(4*pi)]}

Imaginary point pls


Bungie making us do maths

  • 07.13.2012 1:45 PM PDT

Nice read again! Thanks DeeJ.

  • 07.13.2012 1:47 PM PDT
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WyIdfyre: 'lol, who the hell would even wear those?'
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Posted by: RocketMoose
Posted by: Hylebos
Posted by: MozzarellaMonky
h is the height
Ahh, but what is the height in terms of a and r is the question?

:)


Imaginary bonus points for the answer to this one! :)
(I'm guessing Hylebos already solved it - if so, give others a shot at imaginary glory)

a/sinA = b/sinB = c/sinC
b=r
180 - (180-(arccos(1-a/360)) + 90) = B
r/sinB = h/sin(180-(arccos(1-a/360)))
h/sin(180-(arccos(1-a/360))) = z
sin^-1 z = h

I went wrong somewhere, maybe in the last step - but you might be able to extrapolate something from that!

  • 07.13.2012 1:54 PM PDT

DEEDLE LEEDLE LEEDLE DEEEEE

VIDOC!!! WOOT

  • 07.13.2012 1:55 PM PDT

The Song Of Nephilim

Xenoblade <3

I love reading these. I guess you guys did not have a special dinner then xD

  • 07.13.2012 1:56 PM PDT

You better close this sig when your done.

Rumor has it that Paul McCartney is only there to sing happy birthday to all the employees. Is this true?

  • 07.13.2012 1:57 PM PDT

Posted by: Kalriq
Posted by: RocketMoose
Posted by: Hylebos
Posted by: MozzarellaMonky
h is the height
Ahh, but what is the height in terms of a and r is the question?

:)


Imaginary bonus points for the answer to this one! :)
(I'm guessing Hylebos already solved it - if so, give others a shot at imaginary glory)

a/sinA = b/sinB = c/sinC
b=r
180 - (180-(arccos(1-a/360)) + 90) = B
r/sinB = h/sin(180-(arccos(1-a/360)))
h/sin(180-(arccos(1-a/360))) = z
sin^-1 z = h

I went wrong somewhere, maybe in the last step - but you might be able to extrapolate something from that!
Law of sines? Why not Pythagorean Theorem? :)

  • 07.13.2012 2:09 PM PDT
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WyIdfyre: 'lol, who the hell would even wear those?'
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Posted by: Hylebos
Posted by: Kalriq
Posted by: RocketMoose
Posted by: Hylebos
Posted by: MozzarellaMonky
h is the height
Ahh, but what is the height in terms of a and r is the question?

:)


Imaginary bonus points for the answer to this one! :)
(I'm guessing Hylebos already solved it - if so, give others a shot at imaginary glory)

a/sinA = b/sinB = c/sinC
b=r
180 - (180-(arccos(1-a/360)) + 90) = B
r/sinB = h/sin(180-(arccos(1-a/360)))
h/sin(180-(arccos(1-a/360))) = z
sin^-1 z = h

I went wrong somewhere, maybe in the last step - but you might be able to extrapolate something from that!
Law of sines? Why not Pythagorean Theorem? :)
I didn't know if we were allowed to take the hypotenuse as a given.
height = sqrt (hypotenuse^2 - radius^2)

  • 07.13.2012 2:13 PM PDT
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I <3 you too Bungie

Darn you Scott Taylor! Why didn't you answer the question about breaking into the gaming industry!? Production staff matter!

  • 07.13.2012 2:19 PM PDT

Posted by: Kalriq
I didn't know if we were allowed to take the hypotenuse as a given.
height = sqrt (hypotenuse^2 - radius^2)
The hypotenuse is our given as it is equal to the radius of the original paper circle that we cut a wedge of of. The radius you're thinking of is seperate and must be solved for in terms of that original radius and angle a.

  • 07.13.2012 2:19 PM PDT
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R.I.P. DeathPimp. Never Ending Respect.

"Posted by: Kickimanjaro
I'm trying to become an '04, but it's not working too well."

Did someone say Hypotenuse?

  • 07.13.2012 2:19 PM PDT

XBL: l Sonic l
PSN: Sonic_343

Math sucks. Give me a good 1700-present history question.

[Edited on 07.13.2012 2:23 PM PDT]

  • 07.13.2012 2:22 PM PDT
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Posted by: Hylebos
Posted by: Kalriq
I didn't know if we were allowed to take the hypotenuse as a given.
height = sqrt (hypotenuse^2 - radius^2)
The hypotenuse is our given as it is equal to the radius of the original paper circle that we cut a wedge of of. The radius you're thinking of is seperate and must be solved for in terms of that original radius and angle a.

Yeah, if you think about actually forming the party hat you'll see they are the same

  • 07.13.2012 2:23 PM PDT
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Of course, I was visualising it completely wrong.

Sin (180-(arccos(1-a/360))) = opposite/hypotenuse

Opposite = Sin (180-(arccos(1-a/360))) * hypotenuse
h = Sin (180-(arccos(1-a/360))) * a

I think that's right.

  • 07.13.2012 3:01 PM PDT

Check out my Soundcloud account to hear some of my music.
Here's my twitter, in the off-chance you want that too.

Community Joe Interview: defnop552
Bye.

Ninety third!

I made the mail sack!!! :-)

  • 07.13.2012 3:02 PM PDT
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Do not waste your tears, I was not born to watch the world grow dim. Life is not measured in years, but by the deeds of men.

Posted by: goldhawk
We should know better, because we are better.

I too find it awesome how quickly this community works when presented with a riddle. We get 7 symbols and get phone numbers a few hours later. Crazy times.

  • 07.13.2012 3:08 PM PDT

Posted by: Kalriq
Of course, I was visualising it completely wrong.

Sin (180-(arccos(1-a/360))) = opposite/hypotenuse

Opposite = Sin (180-(arccos(1-a/360))) * hypotenuse
h = Sin (180-(arccos(1-a/360))) * a

I think that's right.
Hmmm. Mostly right, but I see two problems:
1) You're subtracting the angle that we found in the original question from 180. The sum of a triangles angles is 180, but that's not the number you should be subtracting from in this case.
2) a is the angle of the wedge we are cutting out of the circle, you meant to say r for the radius of the circle :P

  • 07.13.2012 3:08 PM PDT
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I don't know!
r became the hypotenuse, due to the angles in a straight line being 180, by subtracting the angle found in the original question, we can find the internal slant angle.

  • 07.13.2012 3:12 PM PDT

You want to subtract from 90 :)

  • 07.13.2012 3:38 PM PDT


Posted by: Kalriq
I don't know!
r became the hypotenuse, due to the angles in a straight line being 180, by subtracting the angle found in the original question, we can find the internal slant angle.

The answer doesn't need any trig functions. Like you said, h^2 = r^2 - R^2 (R is what I defined as 2*pi*r-2*pi*r*a). Substitute that for R in the previous expression, solve for h and you should come up with what I had in my previous post (unless I screwed up with the algebra.)

Or wait, are we talking about finding h or the slant angle? I forgot what's going on here lol

  • 07.13.2012 3:58 PM PDT

Posted by: ZosoAchilles
Posted by: Kalriq
I don't know!
r became the hypotenuse, due to the angles in a straight line being 180, by subtracting the angle found in the original question, we can find the internal slant angle.

The answer doesn't need any trig functions. Like you said, h^2 = r^2 - R^2 (R is what I defined as 2*pi*r-2*pi*r*a). Substitute that for R in the previous expression, solve for h and you should come up with what I had in my previous post (unless I screwed up with the algebra.)

Or wait, are we talking about finding h or the slant angle? I forgot what's going on here lol
We're finding h.

  • 07.13.2012 4:00 PM PDT